MAX
Returns the maximum value based upon a column input or grouping of columns.
See also:
[SELECT
]
Syntax
/* aggregate function */
SELECT MAX(columnExpression) FROM <multipartIdentifier>
[ GROUP BY groupByColumn ];
/* scalar (multi-argument) function */
SELECT MAX(scalarExpression1, scalarExpressionN, ...) FROM <multipartIdentifier>;
Arguments
Aggregate function
columnExpression
A column or expression including operands (+
, -
, ...).
The
MAX
function will return the largest value for the given column based upon the column data type, for example aMAX
operation on an integer column will return the largest integer for that column or column grouping, whereas aMAX
operation on a string column or column grouping will return the largest ASCII value (generally the first value when sorted in lexographic order with some differences).
groupByColumn
A column or columns used to perform summary or aggregate operations against. The GROUP BY
clause returns one row for each column grouping.
The
MAX
function ignoresNULL
values.
The
MAX
function returnsNULL
if all the values in the group areNULL
.
Scalar function
scalarExpression
A list columns or expressions (2 or more) from which the largest value is determined and returned.
The scalar
MAX
function returnsNULL
if any argument isNULL
.
The scalar or multi-argument
MAX
function searches its arguments from left to right for an argument that defines a collating function and uses that collating function for all string comparisons.
If none of the arguments the scalar
MAX
function define a collating function, then theBINARY
collating function is used.
If only one argument is provided, then the
MAX
aggregate function is invoked.
Return Value(s)
Returns the maximum value based upon the input data type (or grouping).
Examples
Return the maximum value for a column
SELECT name, location, max(timeCreated)
FROM google.storage.buckets WHERE project = 'stackql';
Return the maximum value for each value in a column
SELECT name, location,
max(round(julianday('now')-julianday(timeCreated))) as age
FROM google.storage.buckets WHERE project = 'stackql'
GROUP BY location;
Return the maximum value from a list of values using the scalar max
function
SELECT max(json_extract(disks, '$[0].diskSizeGb'),json_extract(disks, '$[1].diskSizeGb')) as largest_disk
FROM google.compute.instances
WHERE project = 'stackql-demo'
AND zone = 'australia-southeast1-a';
For more information, see https://www.sqlite.org/lang_aggfunc.html#max_agg or https://www.sqlite.org/lang_corefunc.html#max_scalar